Blog Page 9

### Solve (x + 1)(x – 3) = 0

Solution:The solution to this problem is quite easy. As we can see the above statement has already been factorized for us. All we have to do here is solve the factors separately .(x+1) (x-3)=0x + 1=0  or  x...

### Solve x^2 – 4 = 0

This equation is quite simple and we have two quick and easy ways to arrive at the desired solution.Solution: Method 1:By taking square root on both sides we get:Method 2:By using formula in the above equation we get: where...

### In the following equation, m is a real number. z^2 – (3 + i) z + m + 2 i = 0 Calculate the values of...

Solution:The solution to this problem is quite simple.... Say r is a real root. Then we haveFor m = 2, there is a real root r = 2. But the sum of the roots is 3+i. From this, the second...

### Solve: z^2 = -4i

Solution:The solution to this problem is quite simple.....The two solutions are:

### Solve: i(x^2) +(1-5i)x -1+8i=0

Solution:The solution to this problem is quite simple....

### Show that for each complex number z, z’.z is a real number

The solution to this problem is quite simple But before diving into it's solution, remember the following key points about complex numbers.i^2=-1, So whenever you get i^2, replace it by -1 to further simplify the problem. A complex number is of the form...

### Simplify sqrt(16) . sqrt(-49).i

The solution to this type of problem is quite simple. Before diving into these type of questions,you must remember two key points about complex numbers.sqrt (-1) = i^2, so in case you have a negative square root and you...

### Simplify |z-4|=3

Solution: Here we know that z= x + yi hence |z- 4| =|x+iy-4|=3 =|(x-4)+iy|=3Taking square on B.S  Ans